Difference between revisions of "Preparing Solutions for Making 234mPa Generator"
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Jonpo@uio.no (talk | contribs) (Created page with "To make the 234mPa generator you will need the following solutions: #2 M HCl (37% conc. HCl is 12.5 M) #NaAc + K<sub>4</sub>[Fe(CN)<sub>6</sub>] solution (8 g NaC2H3O2 pluss 40 ...") |
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#2 M HCl (37% conc. HCl is 12.5 M) | #2 M HCl (37% conc. HCl is 12.5 M) | ||
− | #NaAc + K<sub>4</sub>[Fe(CN)<sub>6</sub>] solution (8 g | + | #NaAc + K<sub>4</sub>[Fe(CN)<sub>6</sub>] solution (8 g NaC<sub>2</sub>H<sub>3</sub>O<sub>2</sub> pluss 40 g K<sub>4</sub>[Fe(CN)<sub>6</sub>] per L solution) |
Revision as of 22:17, 4 October 2012
To make the 234mPa generator you will need the following solutions:
- 2 M HCl (37% conc. HCl is 12.5 M)
- NaAc + K4[Fe(CN)6] solution (8 g NaC2H3O2 pluss 40 g K4[Fe(CN)6] per L solution)