# Difference between revisions of "Solutions 2"

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+ | #1000g Th(NO3)4 = 2.083 mol arrow N(Th)= 1.25<math>\cdot</math>10<sup>24</sup> atoms. This is natural thorium, where the equilibrium in Th-series will lead to equal aktivity of <sup>232</sup>Th and <sup>228</sup>Th. Since <sup>232</sup>Th has a incredibly long half-life and <sup>228</sup>Th is short compared to this and we can approximate N(Th)<math>\approx</math>N(<sup>232</sup>Th)=1.25<math>\cdot</math>10^24 The disintegration for both is 1.96<math>\cdot</math>10<sup>6</sup>Bq. | ||

+ | #6.43<math>\cdot</math>10<sup>-8</sup>g | ||

+ | #10000 Bq <sup>228</sup>Ra = 2.62<math>\cdot</math>10<sup>12</sup> atoms = 90% arrow 100% 2.92<math>\cdot</math>10<sup>12</sup> atoms. If <sup>232</sup>Th is N1 and <sup>228</sup>Ra is N2 we can use the formulas for mother/daughter realations:<math>N_{2}=\frac{\lambda_{1}}{\lambda_{2}-\lambda_{1}}N_{1,0}(e^{-\lambda 1\cdot t}-e^{-\lambda 2\cdot t}</math> | ||

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## Revision as of 10:01, 19 June 2012

1:

- 1000g Th(NO3)4 = 2.083 mol arrow N(Th)= 1.25
^{24}atoms. This is natural thorium, where the equilibrium in Th-series will lead to equal aktivity of^{232}Th and^{228}Th. Since^{232}Th has a incredibly long half-life and^{228}Th is short compared to this and we can approximate N(Th) N(^{232}Th)=1.25 10^24 The disintegration for both is 1.96 10^{6}Bq.
10 - 6.43
^{-8}g
10 - 10000 Bq
^{228}Ra = 2.62 10^{12}atoms = 90% arrow 100% 2.92 10^{12}atoms. If^{232}Th is N1 and^{228}Ra is N2 we can use the formulas for mother/daughter realations: