Difference between revisions of "Solutions 7"

From mn/safe/nukwik
Jump to: navigation, search
Line 1: Line 1:
 
This solution set contains a large number of errors, and is under revision. It will be updated as soon as possible.
 
This solution set contains a large number of errors, and is under revision. It will be updated as soon as possible.
 +
 +
Return to [[Problem Solving Sets]]
  
 
For these exercises it might be usfull to have wallet cards they can for instance be found at [http://www.nndc.bnl.gov/nudat2/indx_sigma.jsp Nudat 2]
 
For these exercises it might be usfull to have wallet cards they can for instance be found at [http://www.nndc.bnl.gov/nudat2/indx_sigma.jsp Nudat 2]

Revision as of 10:01, 22 June 2012

This solution set contains a large number of errors, and is under revision. It will be updated as soon as possible.

Return to Problem Solving Sets

For these exercises it might be usfull to have wallet cards they can for instance be found at Nudat 2

1:

  1. [math]\frac{m}{M_{m}}\cdot N_{a}\cdot \% = N [/math]
    [math]\frac{N}{\lambda}=D[/math]
    Where m is mass, Mm is molar mass, Na is avogadros constant, % is the percentage N is the number of atoms λ disintigration constant.
  2. Since the half-life of potassium is so low we can assume that the amount lost due to decay is negligible. The amount of potassium is constant
    [math]G=\frac{D\cdot t\cdot E}{m}[/math]
    where G is dose in J/kg, D is the Disintegration rate, t is the time and E is the energy deposited by the radiation.

2:

  1. [math]D\cdot\lambda=N[/math]
    [math]\frac{N}{N_{a}}\cdot M_{m}=m[/math]
  2. First calculate the effective half-life in the body [math]T_{eff}=\frac{T_{Bi}\cdot T_{phy}}{T_{Bi}+T_{phy}}[/math]